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Home/ Questions/Q 8489631
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T21:52:51+00:00 2026-06-10T21:52:51+00:00

@echo off setlocal EnableDelayedExpansion set i=0 for %%X in (*.jpg;*.png) do ( set ext=%%~xX

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@echo off
setlocal EnableDelayedExpansion
set i=0
for %%X in (*.jpg;*.png) do (
    set ext=%%~xX
    set /a i+=1
    set num=0000!i!
    set name=!num:~-3!
    copy "%%X" "!name!!ext!"
)

Here’s a batch file I put together for renaming some images I have padded to 3 digits (001, 002, …). While it is trivial to just go in and change the padding if I have more than 999 files in a folder, it would probably be more effective to just have the script calculate the padding required.

I am trying to do the following

1 – Get the number of files in the current directory
2 – Set that as the padding and proceed as usual

How can I do this?

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  1. Editorial Team
    Editorial Team
    2026-06-10T21:52:52+00:00Added an answer on June 10, 2026 at 9:52 pm

    You need two loops, in the first loop you only get the count of your files and the string length of the counter.

    Then you set this to a variable ex.

    set padLength=%stringLenOfCounter%
    

    Then you only need to change your second loop to

    for %%X in (*.jpg;*.png) do (
        ...
        set name=!num:~-%padLength%!
        ...
    )
    
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