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Editorial Team
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Asked: 2026-05-13T10:06:25+00:00

echo sed -i ‘s/NULL/\\N/g’ .$_REQUEST[‘para’]..sql; The above statement works. But it fail when I

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echo "sed -i 's/NULL/\\N/g' ".$_REQUEST['para'].".sql";

The above statement works. But it fail when I use it in exec like this…

exec("sed -i 's/NULL//\/\/\N/g' ".$_REQUEST['para'].".sql");
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1 Answer

  1. Editorial Team

    You should escape backslashes with backslashes, not with forward slashes, like this:

    exec("sed -i 's/NULL/\\\\N/g' ".$_REQUEST['para'].".sql");

    EDIT I wrote the answer without looking at what the code actually does. Don’t do this, because $_REQUEST['para'] can be whatever the user wants, which can be used for code injection. Use the PHP functions as the other answer suggests.

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