Question

echo " <table bgcolor='#d3fcfe'   align='center'>  ";

while ($row = mysql_fetch_array($result)) {

echo '</div> <tr onmouseout="this.bgColor=\'#d3fcfe\';"  onmouseover= "this   .bgColor=\'#fffdcd\';" >  ';
 $numq2=$row['username'] ;


{
echo '<td ><div class="iddiv"> <input name="" type="text" value="$numq2" />   <div>    </td> ';
}

echo '  </table>';
}

i want to output $numq2 Var’s data into the value of the textfield.but something is wrong with my code.it prinout the value of textfield as “$numq2”.what’s wrong with my script?

Answer 1

This

echo '<td ><div class="iddiv"> <input name="" type="text" value="$numq2" />   <div>    </td> ';

should become

echo '<td ><div class="iddiv"> <input name="" type="text" value="'.$numq2.'" />   <div>    </td> ';

Notice the '. and .' around your $numq2