Question

EDIT: An initial “float** floats;” was a typo, corrected. Also, “*floats[0] = 1.0;” does work, but “*floats[1] = 1.0;” segfauls at that point. The array is malloced. Compilation has no warnings on pedantic c99.

This worked:

(pseudo:)

void func(int*);
int i;
func(&i);
void func(int* i) {
 func2(i);
}
void func2(int* i) {
 *i = 2;
}

initial value changed to 2.

but this didn’t work:

void func(float**);
float* floats;
func(&floats);
void func(float** floats) {
 func2(floats);
}
void func2(float** floats) {
 *floats[1] = 1.0;
}

segfault on assignment;

Answer 1

Why are you passing a pointer to an array? Have you tried

func(float *floats)
{
  func2(floats);
}

func2(float *floats)
{
  floats[0] = 2;
}