Question

EDIT FIXED by user @jeroen
You have to move the li and a tags inside the while loop.

Thank you for this, F4LLCON

So the final code (not so clean, but works now):

<?php   
$query = mysql_query("SELECT * FROM `apps` ");
while ($query_row = mysql_fetch_assoc($query))
{
?>
<li>
<?php
$meer = $query_row['TITLE'];
$desc_inject = '';
$sub_string = substr($desc_inject, 0, 200);                             
echo $sub_string." " . '' . '<a href="applink.php?id='.$query_row["ID"].'">' . $meer . '</a>';
?>
</li>
<br />
<?php
}
?>

I want a drop-down menu that will show the TITLES out of my MySQL database.
I know how to do everything concerning the ID etc.

The only problem is that the PHP version of the drop-down menu will SELECT all the TITLES in my database and parse it as ONE link.

So instead of

Home
>About
>Contact
>Another

it will look like

Home
>About
 Contact
 Another 

With other words

Home
>About Contact Another

It will not make multiple drop-down links but only one drop-down link

If you for example do:

<div>
<?php
echo $query_row['TITLE'];
?>
</div>

It will make a individual <div></div> for every TITLE in my database, so I thought this method would also work for the drop-down links..

Does anybody know how to fix it so it will make individual <li></li> for every TITLE?

Here is a normal drop-down menu:

<li id="media"><a href=""></a> 
    <ul>
    <li id="1a"><a href="">About</a></li> 
    <li id="1b"><a href="">Contact</a></li> 
    <li id="1b"><a href="">Another</a></li> 
    </ul>
</li>

And here is the PHP drop-down menu:

<li id="media"><a href=""></a> 
<ul>
<li>
<a href="">
<?php   
$query = mysql_query("SELECT * FROM `apps` ");
while ($query_row = mysql_fetch_assoc($query))
{
echo $query_row['TITLE'];
?>
<br />
<?php
}
?>
</a>
</li>
</ul>
</li>

Answer 1

You have to move the li and a tags inside the while loop.

echo '<li><a href="">' . $query_row['TITLE'] . '</a></li>';