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Asked: May 10, 20262026-05-10T22:05:14+00:00 2026-05-10T22:05:14+00:00

EDIT: I found out that I can get it to compile if I cast

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EDIT: I found out that I can get it to compile if I cast the IMetadataType object to the TMetadata type. Why do I need to do this?

EDIT #2: The ‘Values’ property is a .NET dictionary of type <TMetadata, TData>.

I have this generic method:

private void FillMetadata<TMetadata, TData>     (Metadata<TMetadata, TData> oMetadata) where TMetadata : IMetadataType {     IMetadataType o;     oMetadata.Values.Add(o, (TData)(object)GetValue()); } 

I have stripped the implementation to simplify it (I actually use a real object, not the IMetadataType declared here).

My question is, why doesn’t this compile? The compile error is on the Add() method: ‘cannot convert from ‘IMetadataType’ to ‘TMetadata’.’ Isn’t that what the ‘where’ clause on the method is for?

What am I missing?

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  1. 2026-05-10T22:05:15+00:00Added an answer on May 10, 2026 at 10:05 pm

    The where TMetadata : IMetadataType is a constraint for the generic type parameter TMetadata saying it should derive from IMetadataType. Since oMetadata knows only TMetadata and TData as types to work with, you have to use them in your methods body. This should work:

    private void FillMetadata<TMetadata, TData>(Metadata<TMetadata, TData> oMetadata)      where TMetadata : IMetadataType {     TMetadata o;     oMetadata.Values.Add(o, (TData)(object)GetValue()); }  
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