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Home/ Questions/Q 641411
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T21:03:35+00:00 2026-05-13T21:03:35+00:00

[edit] I meant to say command arguments in compiler configs . for the title.

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[edit] I meant to say “command arguments in compiler configs” . for the title.

I am trying to get into game mods. And I am trying to implement the source sdk. one of the steps is to go into debugging in my compiler configurations and add some data to the command arguments

-dev -sw -game "C:\Program Files (x86)\Steam\steamapps\SourceMods\firstmod"

Now I know what command arguments are. They are passed through the parameters of WinMain and judging by the name in the compiler configurations. I assume that has something to do with it. or maybe not. I am just not sure if the above would be considered 1 argument or multiple arguments. and what is it trying to achieve by passing a directory through. They weren’t too detailed with the information.

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  1. Editorial Team
    Editorial Team
    2026-05-13T21:03:36+00:00Added an answer on May 13, 2026 at 9:03 pm

    In a normal (read console) C/C++ application you would have program entry point with the following declaration:

    int main( int argc, char* argv[] );
    

    Here argc is the number of command line “strings”, including the command itself, while argv is the array of these strings. So in your example it’d be argc of 5 (adding the program name), and argv[0] is the name of the program, argv[1] is "-dev", etc.

    Now under Windows a GUI application is different – the entry point is declared as:

    int WINAPI WinMain(      
        HINSTANCE hInstance,
        HINSTANCE hPrevInstance,
        LPSTR lpCmdLine,
        int nCmdShow
    );
    

    So the whole command line (this time excluding the app name) is pointed to by lpCmdLine, so it’d be one string as you put it above. There are helper functions to split that string though. Take a look at these two entries on MSDN:

    • What’s is WinMain
    • How to get normal argv-style command line parameters
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