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Home/ Questions/Q 1089893
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T23:17:40+00:00 2026-05-16T23:17:40+00:00

[edit] I’ve removed my convoluted and badly malformed question so that it doesn’t detract

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[edit]
I’ve removed my convoluted and badly malformed question so that it doesn’t detract from the very neat and correct answer beneath. Given the (surprising) difficulty of finding an on-line example for doing this incredibly common task, I hope Yoni gets a few more up-ticks for his response.

So… the question in a nutshell…

How do I use Apache.Commons to upload a file to some destination. I’m using it in Android and uploading to a PHP script, but obviously it can work from any Java program and to any HTTP based listener.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T23:17:40+00:00Added an answer on May 16, 2026 at 11:17 pm

    From the api of MultipartRequestEntity:

    File f = new File("/path/fileToUpload.txt");
    PostMethod filePost = new PostMethod("http://host/some_path");
    Part[] parts = {
        new StringPart("param_name", "value"),
        new FilePart(f.getName(), f)
    };
    filePost.setRequestEntity(
        new MultipartRequestEntity(parts, filePost.getParams())
    );
    HttpClient client = new HttpClient();
    int status = client.executeMethod(filePost);
    
    • I don’t think you need the content-disposition part, that is used for the other direction (when the browser downloads a file and needs to know what to do with it).
    • getParams.setParameter is optional. You can also set it directly on the HttpClient instance.
    • AFAIK, the order of setting request headers is irrelevant, as long as they are all set before you set the request body.
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