Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 680533
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 14, 20262026-05-14T01:23:00+00:00 2026-05-14T01:23:00+00:00

EDIT : Per Slaks $j(‘#banner-content img’).each(function() { var link = $j(‘#page-tabs li a.’ +

  • 0

EDIT : Per Slaks

$j('#banner-content img').each(function() {
    var link = $j('#page-tabs li a.' + $j(this).attr('class'));

    if ($j(this).is(':visible')) {
        link.addClass('active');
    } else {
        link.removeClass('active');
    }
});

ORIGINAL POST

I have a banner that rotates a series of three images. The active one has a display:block, while the inactive have display:none. I’m trying to match the class for the active image with an tag so that I can add an “active” class to the a tag. Having some trouble writing that function. It’s adding all of the classes for each of the img elements, regardless of whether they’re being displayed or not…

The html markup looks like this:

<div id="banner-area">
    <div class="clearfix" id="promo-boxes-nav">
        <ul id="banner-tabs">
            <li>
                <ul id="page-tabs">
                    <li><a class="t39" href="#">1</a></li>
                    <li><a class="t42" href="#">2</a></li>
                    <li><a class="t49" href="#">3</a></li>                            
                </ul>
            </li>
            <li class="last">&nbsp;</li>
        </ul>
    </div>


    <div id="banner-content">
         <img class="t39" src="http://localhost:8888/1.png" style="position: absolute; top: 0px; left: 0px; display: none; opacity: 0;">                                            
         <img class="t42" src="http://localhost:8888/2.png" style="position: absolute; top: 0px; left: 0px; display: block; opacity: 1;">                                            
         <img class="t49" src="http://localhost:8888/3.png" style="position: absolute; top: 0px; left: 0px; display: none;opacity: 0;">                                        
    </div>
</div>

The function in its current form looks like this:

$j('#banner-content img').each(function() {
    if($j(this).css('display','inline')) {
        var bcClass = $j(this).attr('class');

        $j('#page-tabs li a').each(function() {
            if($j('#page-tabs li a').hasClass(bcClass)) {
                $j(this).addClass(bcClass); 
            }
        });
    }
});
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-14T01:23:01+00:00Added an answer on May 14, 2026 at 1:23 am

    Answer for new question:

    $j(this).show() will show the element.
    You mean

    if($j(this).is(':visible'))
    

    Also, in your selectors, you want to write $j(this), not $j('#banner-content img:visible').

    Finally, the code will be easier to read if you make a separate variable to hold the <a> element, like this:

    var link = $j('#page-tabs li a.' + $j(this).attr('class'));
    
    if ($j(this).is(':visible'))
        link.addClass('active');
    else
        link.removeClass('active');
    

    Answer for old question:

    Your problem is that you’re calling hasClass on all of the links within the inner each call. This will check whether any of the elements has that class, not just the current one.
    You need to change it to if($j(this).hasClass(bcClass)).


    However, your code is needlessly complicated, and can be written much more simply:

     $j('#page-tabs a.' 
            + $j('#banner-content img:visible').attr('class'))
         .addClass('active);
    

    This code calls $j('#banner-content img:visible').attr to find the class of the visible <img> element, then puts the class directly into a jQuery selector.

    Note that you probably also want to call removeClass.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 357k
  • Answers 357k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer The other answers are correct. Here is some code you… May 14, 2026 at 9:40 am
  • Editorial Team
    Editorial Team added an answer you ruin the noConflict concept by reassigning the jquery to… May 14, 2026 at 9:40 am
  • Editorial Team
    Editorial Team added an answer If you get that particular error, you don't actually have… May 14, 2026 at 9:40 am

Related Questions

No related questions found

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.