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Home/ Questions/Q 7762025
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Editorial Team
  • 0
Editorial Team
Asked: June 1, 20262026-06-01T14:17:08+00:00 2026-06-01T14:17:08+00:00

EDIT : proper solution: void add(Student s) { if(root == null) root = new

  • 0

EDIT: proper solution:

void add(Student s)
{
    if(root == null)
        root = new TreeNode(s);
    else
        insert(root,s);        
}

void insert(TreeNode tn, Student s)
{
    if(tn.sVal.compareTo(s) > 0)
    {
        if(tn.left != null)
            insert(tn.left, s);            
        else
        {
            tn.left = new TreeNode(s);
            tn.left.parent = tn;
        }
    }
    else if(tn.sVal.compareTo(s) < 0)
    {
        if(tn.right != null)
            insert(tn.right, s);
        else
        {
            tn.right = new TreeNode(s);
            tn.right.parent = tn;
        }
    }
    balance(tn);
}

I’m trying to inserting to a binary tree using the following:

void add(Student s)
    {
        insert(root,s);
    }

private void insert(TreeNode t, Student s)
{        
    if(t == null)
        t = new TreeNode(s);        
    else if(t.sVal.compareTo(s) > 0)
        insert(t.right, s);
    else if(t.sVal.compareTo(s) < 0)
        insert(t.left,s);                
}

However, the tree remains empty, and I can’t figure out why. I hate to be so vague, but I can’t find an error in the logic. What am I missing?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T14:17:10+00:00Added an answer on June 1, 2026 at 2:17 pm

    Here’s a big hint: Make this change first, then debug from there:

    if (t == null)
        throw new IllegalArgumentException();
    

    And a still bigger hint: When you create the new node, you must also have a reference to its parent so you can add it to the parent.

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