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Home/ Questions/Q 6048555
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T07:28:35+00:00 2026-05-23T07:28:35+00:00

EDIT: SOLVED IT :( AFTER SPENDING HOURS ON IT, IT WAS THE SIMPLEST OF

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EDIT: SOLVED IT 🙁 AFTER SPENDING HOURS ON IT, IT WAS THE SIMPLEST OF SOLUTIONS. CORRECT CODE BELOW.

Ok. So I have the query working where I can look someone up by their phone number. What I want to do is if the phone number I look up doesn’t exist, it just returns the phone number. Here’s what I have so far:

Uri lookupUri = Uri.withAppendedPath(PhoneLookup.CONTENT_FILTER_URI, Uri.encode(phoneNumber)); 

Cursor c = context.getContentResolver().query(lookupUri, new String[]{PhoneLookup.DISPLAY_NAME}, null, null, null);  

while(c.moveToNext()) {
    conname = c.getString(c.getColumnIndexOrThrow(PhoneLookup.DISPLAY_NAME));
    }
    if (conname==null || conname.equals("") || conname.equals("null")) {
        conname = phoneNumber;
    }

if (messages.length > -1) {
    smsToast = conname + ":\n'" + messages[0].getMessageBody() + "'";
    Toast.makeText(context, smsToast, Toast.LENGTH_LONG).show();
    Log.e("Text Thing", conname + " ugh");
    Log.e("Text Thing", phoneNumber);
}

I tried everything to turn conname (the contacts name) back to the phoneNumber. It says conname = null if it doesn’t return anything on the toast. So what am I missing?

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  1. Editorial Team
    Editorial Team
    2026-05-23T07:28:36+00:00Added an answer on May 23, 2026 at 7:28 am

    If c.moveToNext() returns false the first time, then there’s no chance of setting a null conname back to the phone number. You can use c.moveToFirst() to test whether the cursor is empty and assign the phone number to conname in that case.

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