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Home/ Questions/Q 1089787
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T23:16:33+00:00 2026-05-16T23:16:33+00:00

EDIT: This method actually works great and I asked it then found the solution

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EDIT: This method actually works great and I asked it then found the solution later. I added the correct call in the overloaded ShowDialog() method (it’s not exacly an overload, or even an override, but it works just the same. My new question is the one at the bottom.

I have a form in which you click one of three buttons. I have defined an enum for the returned results. I want to make the call:

MyFormResults res = MyForm.ShowDialog();

I can add a new ShowDialog method with this code:

public new MyFormResults ShowDialog()
{
    //Show modal dialog
    base.ShowDialog(); //This works and somehow I missed this

    return  myResult; //Form level variable (read on)
}

I set a form-level variable for the result when the buttons are clicked:

MyFormResults myResult;

private void btn1_click(object sender, EventArgs e)
{
    myResult = MyFormsResults.Result1;
    this.DialogResult = DialogResult.OK; //Do I need this for the original ShowDialog() call?
    this.Close(); //Should I close the dialog here or in my new ShowDialog() function?
}

//Same as above for the other results

The only thing I’m missing is the code to show the dialog (modal) and then return my result. There is no base.ShowDialog() function, so how do I do this?

EDIT: There is a ‘base.ShowDialog()’ and it works. This is my new question here:

Also, is this the best way to do all this and Why?

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T23:16:34+00:00Added an answer on May 16, 2026 at 11:16 pm

    Edit: It’s proberly not a good idea to change the functionality of ShowDialog(), people expect it to return a DialogResult and show the form, I suggest something like my suggestion below. Thus, still allowing ShowDialog() to be used the normal manner.

    You could create a static method on your MyForm, something like DoShowGetResult()

    which would look something like this

    public static MyResultsForm DoShowGetResult()
    {
       var f = new MyForm();
       if(f.ShowDialog() == DialogResult.OK)
       {
          return f.Result;   // public property on your form of the result selected
       }
       return null;
    }
    

    then you can use this

    MyFormsResult result = MyForm.DoShowGetResult();
    
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