Question

EDIT:That was fast. The reason why I have this is because the table is a pivot table between 2 tables one has “id” as primary key and the other “type” primary key

Hello.

I want the following:

Find only find “id” where “type” is 1 AND 2 AND 3

This is not working:

SELECT * FROM `table` WHERE `type` = 1 AND `type` = 2 AND `type` = 3;

The SELECT statment should only return one row (id = 1)

Table

id type
1  1
1  2
1  3

2  1
2  2

3  3

Answer 1

If you only want to know the Id then add the keyword Distinct and just select the id,
where there are records for the three different types …

  Select Distinct id 
  FROM `table` t
  WHERE  Exists (Select * From Table Where id = t.id and Type = '1')
     And Exists (Select * From Table Where id = t.id and Type = '2')
     And Exists (Select * From Table Where id = t.id and Type = '3')

If you want to see the Id and the type then add the type to the select,

 Select Distinct id, Type 
  FROM `table` t
  WHERE  Exists (Select * From Table Where id = t.id and Type = '1')
     And Exists (Select * From Table Where id = t.id and Type = '2')
     And Exists (Select * From Table Where id = t.id and Type = '3')

if you want to see every row that has that id, then leave out the distinct

  Select id, Type 
  FROM `table` t
  WHERE  Exists (Select * From Table Where id = t.id and Type = '1')
     And Exists (Select * From Table Where id = t.id and Type = '2')
     And Exists (Select * From Table Where id = t.id and Type = '3')