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Home/ Questions/Q 1016499
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T10:33:33+00:00 2026-05-16T10:33:33+00:00

El Padrino showed a solution: How to change XML Attribute where an xml element

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El Padrino showed a solution:

How to change XML Attribute

where an xml element can be loaded directly (no for each..), edited and saved!

My xml is:

<?xml version="1.0" encoding="ISO-8859-8"?>
<g>
  <page no="1" href="page1.xml" title="נושא 1">
    <row>
      <pic pos="1" src="D:\RuthSiteFiles\webSiteGalleryClone\ruthCompPics\C_WebBigPictures\100CANON\IMG_0418.jpg" width="150" height="120">1</pic>
    </row>
  </page>
</g>

and I need to select a node by two attributes(1. “no” in the page tag and “pos” in the pic tag)

I’ve found :
How to access a xml node with attributes and namespace using selectsinglenode()

where direct access is possible but beside the fact that I dont understand the solution, I think it uses the xpath object which can’t be modified and save changes.

What’s the best way to

  1. access directly an xml node (I’m responsible that the node will be unique)
  2. edit that node
  3. save changes to the xml

Thanks
Asaf

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T10:33:33+00:00Added an answer on May 16, 2026 at 10:33 am

    Use the new, well-designed XDocument/XElement instead of the old XmlDocument API.

    In your example,

    XDocument doc = XDocument.Load(filename);
    
    var pages = doc.Root.Elements("page").Where(page => (int?) page.Attribute("no") == 1);
    var rows = pages.SelectMany(page => page.Elements("row"));
    var pics = rows.SelectMany(row => row.Elements("pic").Where(pic => (int?) pic.Attribute("pos") == 1));
    
    foreach (var pic in pics)
    {
        // outputs <pic pos="1" src="D:\RuthSiteFiles\webSiteGalleryClone\ruthCompPics\C_WebBigPictures\100CANON\IMG_0418.jpg" width="150" height="120">1</pic>
        Console.WriteLine(pic);
    
        // outputs 1
        Console.WriteLine(pic.Value);
    
        // Changes the value
        pic.Value = 2;
    }
    
    doc.Save(filename);
    
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