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Home/ Questions/Q 8686101
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T22:45:11+00:00 2026-06-12T22:45:11+00:00

EmployeeId, Name, ManagerId 1,Mac Manager, null 2,Sue Supervisor, 1 3,Earl Employee, 2 4,Sam Supervisor,

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EmployeeId, Name, ManagerId
1,Mac Manager, null
2,Sue Supervisor, 1
3,Earl Employee, 2
4,Sam Supervisor, 1
5,Ella Employee, 4

Given: Employee Id = 3

Can you help me with sql to get the employee plus managers up the chain?

In this example the results would be

Earl
Sue
Mac
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T22:45:13+00:00Added an answer on June 12, 2026 at 10:45 pm

    Have a look at Recursive Queries Using Common Table Expressions

    declare @EmpID int = 3;
    
    with C as
    (
      select E.EmployeeId,
             E.Name,
             E.ManagerId
      from YourTable as E
      where E.EmployeeId = @EmpID
      union all
      select E.EmployeeId,
             E.Name,
             E.ManagerId
      from YourTable as E
        inner join C  
          on E.EmployeeId = C.ManagerId
    )
    select C.Name
    from C
    

    SE-Data

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