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Home/ Questions/Q 7078629
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T06:34:17+00:00 2026-05-28T06:34:17+00:00

@Entity @Table(uniqueConstraints = @UniqueConstraint(columnNames = { field1, field2})) public class A extends Model{ public

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@Entity
@Table(uniqueConstraints = @UniqueConstraint(columnNames = { "field1", "field2"}))
public class A extends Model{

  public String field1;
  public String field2;
}

I would like to define my own check constraint by extending play.data.validation.Check so I can display a custom validation message.

However it seems that Check only applies to one field.
Is there another way to do this validation check on multiple fields?

UPDATE – Solution

 @Entity
 @Table(uniqueConstraints = @UniqueConstraint(columnNames = { "field1", "field2"}))
 public class A extends Model{

      @CheckWith(UniqueFieldsCheck.class)
      public String field1;
      public String field2;

    static class UniqueFieldsCheck extends Check {
        public boolean isSatisfied(Object obj, Object o) {
            boolean satisfied = true;
            A a = (A)obj;
            A aA = A.find("byField1AndField2", a.field1, a.field2).first();

            if (aA != null) {
                setMessage("This fields should be unique.");
                satisfied = false;
            }

            return satisfied;
        }
    }
 }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T06:34:18+00:00Added an answer on May 28, 2026 at 6:34 am

    Well no, Play only let’s you validate on each field individually. However you can make you own composite field, that’s contained in a separate class and add it to you main object, something like:

    public class A extends Model{
    
      @CheckWith(value = UniqueUserCheck.class, message = "error.not.unique")
      public ComplexField complexField;
    }
    
    public class ComplexField {
    
      public String field1;
      public String field2;
    
    }
    

    and then apply a custom validator to it (more on those here)

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