Question

<env:Envelope  xmlns:env="http://schemas.xmlsoap.org/soap/envelope/"^M
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"^M
  xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/"^M
  xmlns:xsd="http://www.w3.org/2001/XMLSchema"^M
  xmlns:wsse="http://schemas.xmlsoap.org/ws/2002/07/secext">^M
 <env:Header>^M
         <wsse:Security>^M
                 <wsse:UsernameToken>^M
                         <wsse:Username>user</wsse:Username>^M
                         <wsse:Password>pass</wsse:Password>^M
                 </wsse:UsernameToken>^M
         </wsse:Security> ^M
 </env:Header>

I have been told to post this xml to: https://www.abc.com
I am also given the following method:

public int sendPostRequest(String url, String content, String contentType)
            throws Exception {
        PostMethod post = new PostMethod(url);
        post.setRequestEntity(new StringRequestEntity(content, contentType,
                null));
        boolean success = false;
        String responseBody = null;
        int statusCode;

        try {
            getHttpClient().executeMethod(post);
            success = true;
            statusCode = post.getStatusCode();
            responseBody = post.getResponseBodyAsString();
        } catch (Exception ex) {
            log.error("Marhsalling exception : " + ex.getMessage());
            throw new InvalidRequestException("Marhsalling exception :"
                    + ex.getMessage());
        } finally {
            post.releaseConnection();
        }   

        if ((statusCode != HttpStatus.SC_OK) &&
                (statusCode != HttpStatus.SC_NO_CONTENT)) {
            String error = "Got Bad Http Status - <" + statusCode
                    + "> Info : " + responseBody;
            log.error(error);
            throw new InvalidRequestException(error);
        } else {
            log.debug("Success - " + responseBody);
        }
        return statusCode;
    }

private String footer = "</env:Envelope>";
    private String message = "<InstallService><NewAccount></NewAccount></InstallService>";
    private String payload = header + message + footer;

header I have been told is the XML that I have posted. I am not sure about the content type, it was suggested that it could be XML. The project type should be the dynamic web project using the Tomcat server. I was also told to grab org.apache.commons.httpclient library.

I have been trying to put the pieces together but I’m failing to. I get error at: getHttpClient(), saying that the method could not be resolved. It is same for log and InvalidRequestException could not be resolved. It seems that I have to extend my class to another class which would contain these three methods. Which class could it be? What jars could I be missing? A simple main method which calls the above method and passes the required arguments would work?

Answer 1

/*
     * soapXMLtoEndpoint sends the soapXMLFileLocation to the endpointURL
     */
    public void soapXMLtoEndpoint(String endpointURL, String soapXMLFileLocation) throws SOAPException {
        SOAPConnection connection = SOAPConnectionFactory.newInstance().createConnection();
        SOAPMessage response = connection.call(xmlStringToSOAPMessage(soapXMLFileLocation), endpointURL);
        connection.close();
        SOAPBody responseBody = response.getSOAPBody();
        SOAPBodyElement responseElement = (SOAPBodyElement) responseBody.getChildElements().next();
        SOAPElement returnElement = (SOAPElement) responseElement.getChildElements().next();
        if (responseBody.getFault() != null) {
            System.out.println("fault != null");
            System.out.println(returnElement.getValue() + " " + responseBody.getFault().getFaultString());
        } else {
            serverResponse = returnElement.getValue();
            System.out.println(serverResponse);
            System.out.println("\nfault == null, got the response properly.\n");
        }
    }

Using file in this case, but it can be a simple string. You would have to create a soapmessage out of that string.