Question

environment:

1.EasyUI Datagrid
2.jsp(s2sh)
3.mysql 
//until now i can populate the datagrid plugin with json object normally but a 
  small issue.

describe:

i got a Json-data-object returned from server,like below:

{"total":28,"rows":[{"productid":"1","attr":{"size":"10dc","color":"red&yellow"},
                    {"productid":"2","attr":{"size":"102dc","color":"green&null"}

with the plugins:

$(document).ready(function(){
      $('#tt').datagrid({  
        url:'loadVerifyStream.eAction',
        pagination:true,
        columns:[[  
                {field:'productid',title:'Product ID',width:100},  
                {field:'?????',title:'Product Size',width:250},  
                {field:'?????',title:'product Color',width:100},
       ]]  

});
});

i can’t output ‘Size’ and ‘Color’ attrs to the Grid,I tried

{field:'attr.size',title:'Product Size',width:250},
{field:'attr.color',title:'product Color',width:100},

no work.

anyone knows how to solve this ?
thanks in advance.

//—————————————–
I think i figured this issue out already.

refer to DataGrid’s API:

{field:'color',title:'product Color',width:100,
   formatter:function(val,rec){
   return rec.attr == null ? "":rec.attr.color;

}}

Answer 1

This is a more general solution:

say your json object is the following:

[{id:3,client:{name: "John",city:'New York'},
[{id:4,client:{name: "Paul",city:'Paris'}]

to get the field name in your fomatter function, use this markup:

<table id="dg">
    <thead>  
      <tr>
        <th field="id" width="50">ID</th>
        <th field="not used" formatter="(function(v,r,i){return formatColumn('client.name',v,r,i);})" width="50">Client name</th>
        <th field="not used" formatter="(function(v,r,i){return formatColumn('client.city',v,r,i);})" width="50">Client city</th>
      </tr>  
    </thead>  
</table>

then define formatColumn

function formatColumn(colName, value, row, index) {
    return eval("row."+colName");
}