Question

error in Infopath:

Object reference not set to an instance of an object.
at InfoPathFormTemplate5.FormCode.CTRL407_5_Clicked(Object sender, ClickedEventArgs e)
at Microsoft.Office.InfoPath.Internal.ButtonEventHost.OnButtonClick(DocActionEvent pEvent)
at Microsoft.Office.Interop.InfoPath.SemiTrust._ButtonEventSink_SinkHelper.OnClick(DocActionEvent pEvent)

error in VB2005: Object reference not set to an instance of an object.
System.NullReferenceException was unhandled by user code
Message=”Object reference not set to an instance of an object.”
Source=”InfoPathFormTemplate5″
StackTrace:
at InfoPathFormTemplate5.FormCode.CTRL407_5_Clicked(Object sender, ClickedEventArgs e) in C:\Documents and Settings\pebabczu\Desktop\IntakeForm Copy\InfoPathFormTemplate5\FormCode.cs:line 206
at Microsoft.Office.InfoPath.Internal.ButtonEventHost.OnButtonClick(DocActionEvent pEvent)
at Microsoft.Office.Interop.InfoPath.SemiTrust._ButtonEventSink_SinkHelper.OnClick(DocActionEvent pEvent)

Code:

string TeamL = xnMyForm.SelectSingleNode("/my:myFields/my:field149", ns).Value;
string ACC = xnMyForm.SelectSingleNode("/my:myFields/my:Bank", ns).Value;
string remarkmain = xnMyForm.SelectSingleNode("/my:myFields/my:field104", ns).Value;
string RemarkHR = xnMyForm.SelectSingleNode("/my:myFields/my:Remarks1", ns).Value;
string RemarkTL = xnMyForm.SelectSingleNode("/my:myFields/my:field55", ns).Value;
string RemarkIT = xnMyForm.SelectSingleNode("/my:myFields/my:RemarksICT", ns).Value;
string Rmain = "Remarks: " + remarkmain;
string RHR = "Remarks: " + RemarkHR;
string RTL = "Remarks: " + RemarkTL;
string RIT = "Remarks: " + RemarkIT;

I dont get it… Just getting into C# what did I do wrong.?

Answer 1

Well, you’re dereferencing something that turns out to be null.

It’s hard to say exactly which line of code is problematic out of what you posted, but you should look at line 206. I strongly suspect that SelectSingleNode is returning null for one of your XPath expressions – you’re then trying to access the Value property, which is causing the exception.

So, you need to:

• Work out which line is causing the problem
• Find out whether it’s because the data is wrong or your XPath query
• Consider putting in a nullity check before accessing the value (if you should really, really always find a node, then an exception may well be the right approach already)