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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T14:11:05+00:00 2026-05-15T14:11:05+00:00

Eventually I got the answer, but it puzzled me for a while. Why does

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Eventually I got the answer, but it puzzled me for a while.

Why does the following code throws NullPointerException when run?

import java.util.*;

class WhyNullPointerException {
    public static void main( String [] args ){
       // Create a map
        Map<String,Integer> m = new HashMap<String,Integer>();
        // Get the previous value, obviously null.
        Integer a = m.get( "oscar" );
        // If a is null put 1, else increase a
        int p = a == null ? 
            m.put( "oscar", 1) : 
            m.put( "oscar", a++ ); // Stacktrace reports Npe in this line
    }
}
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  1. Editorial Team
    Editorial Team
    2026-05-15T14:11:06+00:00Added an answer on May 15, 2026 at 2:11 pm

    Because m.put returns null (which indicates that there’s no "previous" value) while you’re trying to assign it to int. Replace int p by Integer p and it will work.

    This is specified in JLS 5.1.8:

    5.1.8 Unboxing Conversion

    At run time, unboxing conversion proceeds as follows:

    • If r is null, unboxing conversion throws a NullPointerException

    Unrelated to the problem, just a side suggestion with DRY in mind, consider writing it so:

        Integer p = m.put("oscar", a == null ? 1 : a++);
    

    It’s a bit more readable 🙂

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