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Home/ Questions/Q 4622090
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T02:47:41+00:00 2026-05-22T02:47:41+00:00

Every time I try to display the category I get the name Array instead

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Every time I try to display the category I get the name Array instead of the category name. I was wondering how can I display the category names from my code below?

$list = array();
$cat = array();
$query = mysqli_query($dbc,"SELECT id, parent_id, category FROM categories ORDER BY parent_id, category LIKE category ASC");
while($row = mysqli_fetch_assoc($query)){
    $list[$row['id']] = array_merge($row, array('children' => array()));
}
mysqli_free_result($query);

foreach($list as $nodeId => &$node) {
    if(!$node['parent_id'] || !array_key_exists($node['parent_id'], $list)){
        $cat[] = &$node;
    } else {
        $list[$node['parent_id']]['children'][] = &$node;
    }
}
unset($node);
unset($list);

Var dump output example.

array
  0 => &
    array
      'id' => string '1' (length=1)
      'parent_id' => string '0' (length=1)
      'category' => string 'Cat-1' (length=5)
      'children' => 
        array
          0 => &
            array
              ...
          1 => &
            array
              ...
          2 => &
            array
              ...
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T02:47:41+00:00Added an answer on May 22, 2026 at 2:47 am

    When you echo a variable, and the browser display’s “Array”, you need to go another level deeper to access the array elements. You may have tried this already, but var_dump() your category array to view the structure of your array and verify it is what you expected it to be. YOu will be able to analyze your apparent multi-dimensional array to judge how many loops you need to get to the category names.

    Update:

    to go a level deeper, you need nested loops. for example:

    foreach($first_level as $first){
        foreach($first as $second_level){
            echo $second_level;
        }
    }
    
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