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Home/ Questions/Q 7032091
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T00:53:22+00:00 2026-05-28T00:53:22+00:00

everybody knows that interrupt handler should be short as possible. and adding functions like

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everybody knows that interrupt handler should be short as possible. and adding functions like printk for debugging inside an interrupt handler is something that shouldn’t be done.
Actually, I tried it before when I was debugging the linux kernel for an interrupt driven char device I written, and it wrecked the timing of the driver.

The question I have, is why this is happening ?
printk function is buffered ! it means, as far as I understand that the data is inserted in to a queue, and it’s being handled later, most probably after the interrupt handler is finished.

So why doesn’t it work ?

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  1. Editorial Team
    Editorial Team
    2026-05-28T00:53:23+00:00Added an answer on May 28, 2026 at 12:53 am

    The printk function is not just inserting into a queue/buffer — assuming the log level is high enough, the output from printk will be emitted to the console immediately, as part of the call to printk. This is especially slow if the console is, say, on a serial port. But in any case, printk does introduce pretty substantial overhead and can affect timing.

    If you have a timing critical place where you want to get some debug output, you can look at using the trace_printk function in modern kernels. This actually does just put input into the trace ringbuffer, and you can read it later. Take a look at this article for full details.

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