Question

Example code below;

function a() {
    var a = 123;
    //some stuff
    b();
}

function b() {
    //some stuff
}

a();

So my question is whether the variable ‘a’ is in memory while b() is executed ?

Thank you.

Answer 1

Yes it is. It’s not in b()‘s scope, but it is in memory.

You can’t just magically delete objects withing a()‘s scope. You could manually delete a; if you wouldn’t need it anymore, but the best and most reasonable way to do this is by calling them one after the other instead of nested calls:

function a() {
    var a = 123;
    //some stuff
}

function b() {
    //some stuff
}

a();
b();

If there is not a quick way to do this, consider refactoring your code a bit