Question

Example:

here is the string: "blablabla123:550:404:487blablabla500:488:474:401blablablabla"

here is what I’m using:

string reg = "(\\d{1,3}):(\\d{1,3}):(\\d{1,3}):(\\d{1,3})";

this obviously doesn’t work since it is looking for starting with the number,
and I also want to fetch all results, but I don’t know how to do that, even though I looked so much for it. :/

I want to have like 2 arrays with:

Array 1: should return [1] = “123”; [2] = “550”; [3] = “404”; [4] =
“487”;
Array 2: should return [1] = “500”; [2] = “488”; [3] = “474”;
[4] = “401”;

#include <regex>
#include <iostream>
#include <string>

#include <conio.h>
using namespace std;

typedef std::tr1::match_results<std::string::const_iterator> str_iterator;
int main () {
    str_iterator res;

string regex = "(\\d{1,3}):(\\d{1,3}):(\\d{1,3}):(\\d{1,3})";
string str = "blablabla123:550:404:487blablabla500:488:474:401blablablabla";
const std::tr1::regex pattern(regex.c_str());
bool valid = std::tr1::regex_match(str, res, pattern);
//res is gonna be an array with the match results
if(valid){
    printf("Matched with size of %d\n", res.size());
    printf("Result 1: %s",res[1]);
    printf("Result 2: %s",res[2]);
    printf("Result 3: %s",res[3]);
    printf("Result 4: %s",res[4]);
}else{
    printf("Not Matched");
}
_getch();
return 0;
}

Answer 1

regex_match will try to match the entire string. Obviously in your case, the result will be false (it won’t match).

Try to use regex_search instead.