Question

example: http://jsfiddle.net/kuTLf/

code looks like this:

<div id="main">
        <div id="slideshow" class="pics">
            <div id="nav"></div>
            <img src="http://cloud.github.com/downloads/malsup/cycle/beach1.jpg" width="200" height="200" />
            <img src="http://cloud.github.com/downloads/malsup/cycle/beach2.jpg" width="200" height="200" />
            <img src="http://cloud.github.com/downloads/malsup/cycle/beach3.jpg" width="200" height="200" />
        </div>
</div>

js:

$(function() {
    $('#slideshow').cycle({
        fx:     'turnDown',
        speed:  'fast',
        timeout: 3000,
        pager:  '#nav',
        slideExpr: 'img'
    });
});

How can I add current active class to current img? like <img class='active>

Answer 1

$('#slideshow').cycle({
    after: function(el, next_el) {
        $(next_el).addClass('active');
    },
    before: function(el) {
        $(el).removeClass('active');
    }
});