Question

example:

SELECT country 
FROM data
WHERE city LIKE 
(SELECT LEFT ('jakartada',7));

it’s working nicely but if i give delimiter with value:4 ,i must give wildcard
like this —> “%string%” ,where i can give wildcard in the query?

Answer 1

With LIKE you can use the following two wildcard characters in the pattern.

Character   Description
%           Matches any number of characters, even zero characters
_           Matches exactly one character
\%          Matches one “%” character
\_          Matches one “_” character

does this query help you?

SELECT country 
FROM data
WHERE city LIKE CONCAT ('%', (SELECT LEFT ('jakartada',7)), '%');