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Home/ Questions/Q 3612502
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T22:00:26+00:00 2026-05-18T22:00:26+00:00

Excuse the beginner level of this question. I have the following simple code, but

  • 0

Excuse the beginner level of this question. I have the following simple code, but it does not seem to run. It gets a segmentation fault. If I replace the pointer with a simple call to the actual variable, it runs fine… I’m not sure why.

struct node
{
 int x;
 struct node *left;
 struct node *right;
};

int main()
{
 struct node *root;
 root->x = 42;
 printf("Hello world. %d", root->x);
 getchar();
 return 0;
}

What is wrong with this code?

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  1. Editorial Team
    Editorial Team
    2026-05-18T22:00:27+00:00Added an answer on May 18, 2026 at 10:00 pm
    struct node *root;
    root->x = 42;
    

    You’re dereferencing an uninitialized pointer. To allocate storage for the node:

    struct node *root = malloc(sizeof(struct node));
    

    You could also allocate a node on the stack:

    struct node root;
    root.x = 42;
    
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