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Home/ Questions/Q 522469
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T08:21:26+00:00 2026-05-13T08:21:26+00:00

Exposition: In general, Reference Counting has the weakness of "it can’t detect loops." However,

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Exposition:

In general, Reference Counting has the weakness of "it can’t detect loops." However, in some cases, Reference Counting is really useful:

class EmergencyPatient {
  DoctorPtr doctor;
  EmergencyPatient() { doctor = Doctor::acquire(); }
  ~EmergencyPatient() { Doctor::release(doctor); } 
};

Now, in a reference counted world, as soon as we no longer refer to an EmergencyPatient, the doctor is released.

In Java’s non-refcounted world, this depends largely on when the EmergencyPatient is garbage collected — and since the garbage collector is generational, the EmergencyPatient can be in an older generation, and not collected for a long time.

Problem:

To me, a doctor is a very precious resource; other EmergencyPatient need doctors. However, to Java, the EmergencyPatient object is just a few bytes of memory.

Question:

What is the right way to solve this problem? (There are some resources that I want to be freed as soon as I know they’re no longer being used).

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-13T08:21:27+00:00Added an answer on May 13, 2026 at 8:21 am

    If you examine the 4 reference objects, there is one that will notify you when your object becomes “Eligible for garbage collection”. This means that you don’t have to wait for a “Big” GC, it can let you know during one of the minor passes if your object has become unreachable, even if it’s in one of the older generation areas.

    I believe this is supposed to be the correct way to do what you are attempting.

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