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Home/ Questions/Q 494821
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T05:32:05+00:00 2026-05-13T05:32:05+00:00

Facts: I have a TabControl with 2 Tabs, Each tab has 2 DateTimePicker. In

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Facts:

  • I have a TabControl with 2 Tabs, Each tab has 2 DateTimePicker.
  • In the Load event, I set the value of all the DTPs.
  • All DTPs have ShowCheckBoxes set on true AND Checked set on false.
  • When I Execute the program, The DTPs in first tab are OK, but when I check the DTPs on second tab, they show current time, not the time I set on the load event.

Why this happen? How can I avoid it?

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  1. Editorial Team
    Editorial Team
    2026-05-13T05:32:05+00:00Added an answer on May 13, 2026 at 5:32 am

    My ugly workaround to this issue, consists on set active the tab in which the DTP’s reside before changing its values, something like this:

    DateTime dat1 = DateTime.Today;
    DateTime dat2 = dat1.AddDays(1).AddSeconds(-1);
    
    dtpCreatedStart.Value = dat1;
    dtpCreatedEnd.Value = dat2;
    tbc.SelectTab(1);
    dtpModifiedStart.Value = dat1;
    dtpModifiedEnd.Value = dat2;
    tbc.SelectTab(0);
    
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