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Editorial Team
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Asked: 2026-05-29T17:59:54+00:00

Few hours ago I have started to learn java socket comunication. Now I’m trying

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Few hours ago I have started to learn java socket comunication. Now I’m trying to make server application whitch should return me data to webbrowser.
My code:

try{
    ServerSocket socket = new ServerSocket(80);
    Socket response = socket.accept();
    String lol = "<html>hi</html>";
    OutputStream str = response.getOutputStream();
    str.write(lol.getBytes("US-ASCII"));
    str.flush();
    response.close();
    System.out.println("LOL works!");
    }catch(IOException ex)
    {
        System.out.println(ex.toString());
    }
}

I have no error in server application, the message “LOL works!!!” prints in console but in webbrowser I’m getting this error:

My error.

Does anobody know how to repair it and get the text “hi” in webbrowser? Thanks.

EDIT:
I’ve tried add it to telnet. This is the result:
Telnet result

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1 Answer

  1. Editorial Team

    You cannot just send out raw data to the browser and expect it to handle it – you have to follow the HTTP (protocol) which is described in RFC1945.

    Specifically, you have to send out a few headers followed by a new line first as described in Section 4.1 of RFC1945.

    try{
    ServerSocket socket = new ServerSocket(80);
    Socket response = socket.accept();
    String lol = "<html>hi</html>";
    writer = new PrintStream(response.getOutputStream());
    writer.println("HTTP/1.1 200 OK");
    writer.println("Content-Type: text/html");
    writer.println();
    writer.println(lol);
    writer.flush();
    response.close();
    System.out.println("LOL works!");
    }catch(IOException e)
    {
        e.printStackTrace();
    }
}

    Note that I’ve also wrapped your OutputStream in a PrintStream, since this is a lot easier than handling the OutputStream manually.

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