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Home/ Questions/Q 6937541
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T12:22:36+00:00 2026-05-27T12:22:36+00:00

Filtering works fine for an object ( data ) wrapping around an array of

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Filtering works fine for an object (data) wrapping around an array of objects:

var arr = {"data":
 [
  {"name":"Alan","height":"171","weight":"66"},
  {"name":"Ben","height":"182","weight":"90"},
  {"name":"Chris","height":"163","weight":"71"}
 ]
};

var new_arr = $.extend(true, arr);

new_arr.data = $.grep(new_arr.data, function(n, i){
  return n.weight > 70;
});

alert(new_arr.data.length); // answer is 2

However, filtering without the object wrapper doesn’t.

var arr = [
  {"name":"Alan","height":"171","weight":"66"},
  {"name":"Ben","height":"182","weight":"90"},
  {"name":"Chris","height":"163","weight":"71"}
 ];

var new_arr = $.extend(true, arr);

new_arr = $.grep(new_arr, function(n, i){
  return n.weight > 70;
});

alert(new_arr.length); // answer is 1 instead of 2

I am not sure where is the problem. Can anyone point out. Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T12:22:37+00:00Added an answer on May 27, 2026 at 12:22 pm

    You’re using extend incorrectly. You can’t extend the new_arr with an array. Extend will add methods/props to an object but what methods/props will it create when it runs into your array? This is why it works with the object wrapper: 1) extend expects an object and 2) ‘data’ is a property that can be added to new_arry.

    Despite, in your second example, it doesn’t look like you need to extend anything. Does this work?

    new_arr = $.grep(arr, function(n, i){ // just use arr
      return n.weight > 70;
    });
    
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