Question

find `pwd` -type f -name "*.ksh" -exec grep -H ".ksh" '{}' \; -print 2>/dev/null

On Executing this command , the result is

/home/edwprod/Partner_com/bin/edw_etl_job_load.ksh:# Program Name :     edw_etl_job_load.ksh
/home/edwprod/Partner_com/bin/edw_etl_job_load.ksh
/home/edwprod/Partner_com/bin/exec_housekeep_main.ksh:# Program Name     :  exec_housekeep_main.ksh
/home/edwprod/Partner_com/bin/exec_housekeep_main.ksh:# Called program   :  exec_housekeep.ksh
/home/edwprod/Partner_com/bin/exec_housekeep_main.ksh:#!/bin/ksh
/home/edwprod/Partner_com/bin/exec_housekeep_main.ksh:    nohup ${SHELL_DIR}/exec_housekeep.ksh ${ROOT_ID} ${PLAN_ID} ${P_ACTION} ${LVL} &
/home/edwprod/Partner_com/bin/exec_housekeep_main.ksh
/home/edwprod/Partner_com/bin/retrive_pwd_edw.ksh:#        echo "  USAGE=> filename.ksh appl_schema"
/home/edwprod/Partner_com/bin/retrive_pwd_edw.ksh
/home/edwprod/Partner_com/bin/exec_pr_truncate_hkp.ksh:# Program Name     :  exec_pr_truncate_hkp.ksh
/home/edwprod/Partner_com/bin/exec_pr_truncate_hkp.ksh:# Calling program  :  exec_pr_truncate_hkp.ksh
/home/edwprod/Partner_com/bin/exec_pr_truncate_hkp.ksh
/home/edwprod/Partner_com/bin/exec_pr_post_housekeep.ksh:# Program Name     :  exec_pr_post_housekeep.ksh
/home/edwprod/Partner_com/bin/exec_pr_post_housekeep.ksh:# Calling program  :  exec_pr_post_housekeep.ksh
/home/edwprod/Partner_com/bin/exec_pr_post_housekeep.ksh

The command searches all the shell scripts and find the name of scripts being called inside. I need to exactly fetch the ksh name alone from this result. Please help on this?

Answer 1

You could give this a shot (-E is for extended regex, -o is for the output only matching pattern):

find `pwd` -type f -name "*.ksh" -exec grep -E -o "[a-zA-Z0-9_]*\.ksh" '{}' \;

To get a unique list:

find `pwd` -type f -name "*.ksh" -exec grep -E -o "[a-zA-Z0-9_]*\.ksh" '{}' \; |sort -u

Hope this helps!