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Home/ Questions/Q 6779489
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T16:23:28+00:00 2026-05-26T16:23:28+00:00

Firebug is showing an error when I execute this code: $.ajax({ type: GET, url:

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Firebug is showing an error when I execute this code:

$.ajax({
type: "GET",
url: "../foos/.....",
dataType: "json",
success: function (foos, textStatus, XMLHttpRequest) {
    for (var i = 0; i <= foos.length; i++) {
        var foo = foos[i];
        alert(foo.id);
    };
}});

The json returns a var “foos” with id and name properties.
even alerting the foo.id propertie, firebug shows the error:

alert(foo.id) //foo is undefined

Why is foo undefined when it is correctly displayed in the alert?

EDIT:
I assigned foo twice, sorry. But even if I don’t do that, i have the same firebug error.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T16:23:28+00:00Added an answer on May 26, 2026 at 4:23 pm

    Which foo did you want? The foo from the array (foos) or the foo you re-declare within the loop:

    for (var i = 0; i <= foos.length; i++) {
        var foo = {
            id: "",
            name:""
        };
    
        var foo = foos[i];
        alert(foo.id);
     };
    

    But, crucially, this isn’t the problem. The problem is that you loop from 0 to foos.length:

    for (var i = 0; i <= foos.length; i++)
    

    Which means on the last iteration of the loop, the index i is 1 greater than the maximum index of the array. When you try to read this element it is, indeed, undefined.

    You should change your loop to:

    for (var i = 0; i < foos.length; i++)
    

    (and of course get rid of the redefined foo).

    Result should be:

    for (var i = 0; i < foos.length; i++) {
        var foo = foos[i];
        alert(foo.id);
     };
    
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