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first :: (a,b,c) -> a
first (x, _, _) = x
second :: (a,b,c) -> b
second (_,y,_) = y
third:: (a,b,c)-> c
third (_,_,z) => z
I got error message from this piece of code.
"parse error on input `=>'
"
I cannot see any reason. Could anyone help me to point out?
thanks.
You used bad lexeme: in first and second
=and in third=>. Replace it with=.