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Home/ Questions/Q 7898569
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T08:28:06+00:00 2026-06-03T08:28:06+00:00

first, here is some code: class A { public: A() { //… readTheFile(mySpecialPath); //…

  • 0

first, here is some code:

class A
{
public:
    A()
    {
        //...
        readTheFile(mySpecialPath);
        //...
    }

    A(boost::filesystem::path path)
    {
        //...
        readTheFile(path);
        //...
    }

protected:  
    void readTheFile(boost::filesystem::path path)
    {
        //First, check whether path exists e.g. by
        //using boost::filesystem::exists(path).
        //But how to propagate an error to the main function?
    }

    //...
};
int main(int argc, char **argv)
{
    A myClass;

    //Some more code which should not be run when A::readTheFile fails
}

What is a good solution to let the main function know that A::readTheFile could not open the file? I want to terminate the execution when opening the file fails.

Many thanks in advance!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T08:28:08+00:00Added an answer on June 3, 2026 at 8:28 am

    Have readTheFile() throw an exception:

    protected:  
        void readTheFile(boost::filesystem::path path)
        {
            //First, check whether path exists e.g. by
            //using boost::filesystem::exists(path).
            //But how to propagate an error to the main function?
            if (/*some-failure-occurred*/)
            {
                throw std::runtime_error("Failed to read file: " + path);
            }
        }
    
    ...
    
    int main()
    {
        try
        {
            A myObj;
    
            //Some more code which should not be run when A::readTheFile fails
        }
        catch (const std::runtime_error& e)
        {
            std::cerr << e.what() << "\n";
        }
    
        return 0;
    }
    
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