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Home/ Questions/Q 8864865
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T16:21:39+00:00 2026-06-14T16:21:39+00:00

First, I tried to use Map<Integer, Set<Integer>> map = new HashMap<Integer, HashSet<Integer>>(); , but

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First, I tried to use

Map<Integer, Set<Integer>> map = new HashMap<Integer, HashSet<Integer>>();

, but it did not compile because no casting is available.

Then I tried

Map<Integer, ? extends Set<Integer>> map = new HashMap<Integer, HashSet<Integer>>();

. It seemed to work, but when I tried to call

map.put(i, new HashSet<Integer>());

, it turned out to be a failure due to uncompatibility.

How can I solve the problem?

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  1. Editorial Team
    Editorial Team
    2026-06-14T16:21:40+00:00Added an answer on June 14, 2026 at 4:21 pm

    You can simply do this:

    Map<Integer, Set<Integer>> map = new HashMap<Integer, Set<Integer>>();
    map.put(1, new HashSet<Integer>());
    

    When you retrieve the value from the map, then it will be of type Set<Integer>, but that shouldn’t make any difference as per your expectation. But if you want to retrieve only HashSet<Integer> then your map definition should be

    Map<Integer, HashSet<Integer>> map = new HashMap<Integer, HashSet<Integer>>();
    
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