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Home/ Questions/Q 153759
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Asked: May 11, 20262026-05-11T09:51:29+00:00 2026-05-11T09:51:29+00:00

First, I’m new to Python, so I apologize if I’ve overlooked something, but I

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First, I’m new to Python, so I apologize if I’ve overlooked something, but I would like to use dict.fromkeys (or something similar) to create a dictionary of lists, the keys of which are provided in another list. I’m performing some timing tests and I’d like for the key to be the input variable and the list to contain the times for the runs:

def benchmark(input):     ...     return time_taken  runs = 10 inputs = (1, 2, 3, 5, 8, 13, 21, 34, 55) results = dict.fromkeys(inputs, [])  for run in range(0, runs):     for i in inputs:         results[i].append(benchmark(i)) 

The problem I’m having is that all the keys in the dictionary appear to share the same list, and each run simply appends to it. Is there any way to generate a unique empty list for each key using fromkeys? If not, is there another way to do this without generating the resulting dictionary by hand?

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  1. 2026-05-11T09:51:29+00:00Added an answer on May 11, 2026 at 9:51 am

    The problem is that in

    results = dict.fromkeys(inputs, []) 

    [] is evaluated only once, right there.

    I’d rewrite this code like that:

    runs = 10 inputs = (1, 2, 3, 5, 8, 13, 21, 34, 55) results = {}  for run in range(runs):     for i in inputs:         results.setdefault(i,[]).append(benchmark(i)) 

    Other option is:

    runs = 10 inputs = (1, 2, 3, 5, 8, 13, 21, 34, 55) results = dict([(i,[]) for i in inputs])  for run in range(runs):     for i in inputs:         results[i].append(benchmark(i)) 
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