Question

First, i’m read the documentation as follow

http://download.oracle.com/javase/1.4.2/docs/api/java/util/regex/Pattern.html

And i want find any punctuation character EXCEPT @’,& but i don’t quite understand.

Here is :

public static void main( String[] args )
{       
     // String to be scanned to find the pattern.
     String value = "#`~!#$%^";
     String pattern = "\\p{Punct}[^@',&]";

    // Create a Pattern object
    Pattern r = Pattern.compile(pattern, Pattern.CASE_INSENSITIVE);

    // Now create matcher object.
    Matcher m = r.matcher(value);
    if (m.find()) {
       System.out.println("Found value: " + m.groupCount());
    } else {
       System.out.println("NO MATCH");
    }


}

Result is NO MATCH.
Is there any mismatch ?

Thanks
MRizq

Answer 1

You’re matching two characters, not one. Using a (negative) lookahead should solve the task:

(?![@',&])\\p{Punct}