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Home/ Questions/Q 8945647
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T12:17:47+00:00 2026-06-15T12:17:47+00:00

first: LPCTSTR asdfsdf = (LPCTSTR)(_bstr_t)v; printf(%s\n, asdfsdf); second: printf(%s\n, (LPCTSTR)(_bstr_t)v); they are the same,

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first:

LPCTSTR asdfsdf = (LPCTSTR)(_bstr_t)v;
printf("%s\n", asdfsdf);

second:

printf("%s\n", (LPCTSTR)(_bstr_t)v);

they are the same, but the first condition causes unreadable code

why?

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  1. Editorial Team
    Editorial Team
    2026-06-15T12:17:48+00:00Added an answer on June 15, 2026 at 12:17 pm

    The _bstr_t class encapsulates a BSTR inside a C++ class. In your first instance:

    LPCTSTR asdfsdf = (LPCTSTR)(_bstr_t)v;
    

    you are creating a _bstr_t object, extracting the LPCTSTR out of it, but then the temporary _bstr_t object gets destructed. Whatever asdfsdf pointed to is now deallocated and can no longer be used.

    In your second example

    printf("%s\n", (LPCTSTR)(_bstr_t)v);
    

    the temporary _bstr_t object is not destructed until after the printf() is called, so there is no problem using the LPCTSTR value.

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