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Home/ Questions/Q 8887447
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T21:48:37+00:00 2026-06-14T21:48:37+00:00

First of all I’m new in web development so sorry if its a dumb

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First of all I’m new in web development so sorry if its a dumb question,I have an array, that the keys of the array are the id of the records that need to be updated in the database, i came with the bellow code to create the query and using mysql transaction to run the query (since few records should be updated together). the generated query works fine when i run it using command line, but with php code NO!

The code to generate the query :

$insert="";

if($run==true){

foreach($result as $key=>$x){


    $insert = $insert ."update project set type='".$x."' "."where "."id=".$key.";";


    }

//echo $insert;
$insert=$insert ."COMMIT;";
$insert= "START TRANSACTION;". $insert;

The result of the code:

START TRANSACTION;update project set type='project1' where id=1;update project set type='project2' where id=2;COMMIT;

The error that it gives me:

Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'update project set type='project1' where id=1;update project set type='project2'' at line 1

I did not include the sql connections and… since i believe in high percentage they are fine, but in case its necessary i can include them too.

Thanks in advance

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  1. Editorial Team
    Editorial Team
    2026-06-14T21:48:39+00:00Added an answer on June 14, 2026 at 9:48 pm

    You might want to switch to PDO which has an interface to transactions directly.

    $db = new PDO($dsn, $user, $pass);
    
    $stmt = $db->prepare("update project set type= ? where id= ?");
    $db->beginTransaction();
    
    try {
      foreach ($result as $key => $x) {
        $db->execute(array($x, $key));
      }
    
      $db->commit();
    } catch (PDOException $e) {
      $db->rollBack();
      throw $e;
    }
    
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