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Editorial Team
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Asked: 2026-05-15T01:28:54+00:00

First of all I’m using netbeans as my IDE and I don’t know if

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First of all I’m using netbeans as my IDE and I don’t know if this is causing it. When I run my program (even if I have build it and run the .jar) I think it selects the tab that was previously selected (before quiting). So if for example I close the app with the third tab selected, it starts up with that selected again. Is there a known solution for this? The selectedIndex property on the jTabbedPane is set to 0. Shouldn’t this property be the default onLoad value?

Thx in advance, Jimmy

PS. BTW for some reason it didn’t submit my question in Opera (?)

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1 Answer

  1. Editorial Team

    Same problem here with Netbeans 6.8 and JTabbedPane. Neither setSelectedIndex() nor setSelectedComponent() makes a difference. The getSelectedIndex() returns the value previously set, but the pane is not selected correctly.

    The reason for this is that the SingleFrameApplication saves it’s state and restores the saved state on the next restart. This is done in the code generated by the GUI builder.
    You could see that startup() and configureWindow() methods of the SingleFrameApplication are overridden.

    Workarounds:

    1. You could override the shutdown() method as well, then modifications to the configuration will not be saved. Note that the original will still be restored, so ensure that the required configuration is saved.

    2. Modifying the startup() method also helps:

    MyView myView = new MyView(this);
myView.getFrame().setVisible(true);
myView.getFrame().pack();
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