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Editorial Team
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Asked: 2026-05-27T03:34:03+00:00

First of, I’m new to ajax and Java Script.. I have spend days solving

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First of, I’m new to ajax and Java Script.. I have spend days solving this problem, but I still haven’t figured it out. I have read through threads with similar problems but I still can’t get it right. So here goes;

Quite simple I want post the checked value from from one of three radio buttons. All I get though is only the value of the first radio button..

I have tried several things, but I stripped down the code so it might be easier see where the problem is 🙂

The ajax

<script type"text="" javascript"="">
$(document).ready(function(){
    $("form#submit").submit(function() {
    // we want to store the values from the form input box, then send via ajax below
    var svar     = $('#svar').attr('value');
    var date     = $('#date').attr('value');
    var email     = $('#email').attr('value');

        $.ajax({
            type: "POST",
            url: "ajax.php",
            data: "svar="+ svar + "&email=" + email + "&date=" + date,
            success: function(){
                $('form#submit').hide();
                //$('form#submit :input').val("");
                $('div.success').fadeIn();
            }
        });
    return false;
    });
});
</script>

The form

<form id="submit" method="post" name="submit" action="">
            <fieldset>
            <legend>Dagens spørgsmål: <? echo $row['question'];?></legend>
                <br>
                <input type="radio" name="svar" id="svar" value="1"><? echo $row['opt1'];?>
                <br>
                <input type="radio" name="svar" id="svar" value="2"><? echo $row['opt2'];?>
                <br>
                <input type="radio" name="svar" id="svar" value="3"><? echo $row['opt3'];?>
                <br>
                    <input name="email" id="email" type="hidden" value="<? echo $email  ?>" />
                    <input name="date" id="date" type="hidden" value="<? echo $date  ?>" />

                <br><br>
                <button type="submit" class="button positive"> <img src="img/tick.png" alt=""> Svar på dagens spørgsmål </button>
            </fieldset>
        </form>

Ajax.php

<?php

    include ("dbc.php");

// CLIENT INFORMATION
    $email        = htmlspecialchars(trim($_POST['email']));
    $date        = htmlspecialchars(trim($_POST['date']));
    $svar        = htmlspecialchars(trim($_POST['svar']));



//stuff from answers

        mysql_query("INSERT INTO answers
        (`email`,`day`,`answer`)
        VALUES
        ('$email','$date','$svar')") or die(mysql_error());

?>

Hope one you of you smart guys have a solution.. because this thing i driving me crazy

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1 Answer

  1. Editorial Team

    You have several problems.

    First, your HTML is invalid. An ID must be unique, so each radio button must have its own ID. You associate a group of radio buttons by giving them the same NAME. (Having a unique ID then lets you associate a LABEL with each one using the FOR attribute which increases accessibility by making it easier for screen readers and providing bigger click targets).

    Second, the value of a radio button is fixed. The question is “Is it successful or not?” and that is determined by seeing if it is checked or not. If you were doing this manually, you would have to loop over each radio button in the group until you found one that was checked (or use a selector that matched only the checked ratio button (:checked)).

    Third, you are building your form data by mashing together strings without making sure the data is URL safe (with encodeURIComponent).

    The solution is to forget about doing all this manually and just use the jQuery serialize method on the form.

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