Question

First off, this is NOT a duplicate of: Turn a C string with NULL bytes into a char array , because the given answer doesn’t work when the char *‘s are Unicode.

I think the problem is that because I am trying to use UTF-8 encoded char *’s instead of ASCII char *’s, and the length of each character is different and thus, this doesn’t work :

char *Buffer;             // your null-separated strings
char *Current;            // Pointer to the current string
// [...]
for (Current = Buffer; *Current; Current += strlen(Current) + 1)
  printf("GetOpenFileName returned: %s\n", Current);

Does anyone have a similar solution that works on Unicode strings?

I have been banging my head on the this for over 4 hours now. C doesn’t agree with me.

EDIT: I think that the problem is that the char * is now UTF-8 instead of ASCII.

Answer 1

Don’t use char*. Use wchar_t* and the related functions

wchar_t *Buffer;             // your null-separated strings
wchar_t *Current;            // Pointer to the current string
// [...]
for (Current = Buffer; *Current; Current += wstrlen(Current) + 1)
  wprintf(L"GetOpenFileName returned: %s\n", Current);

Incidentally, wchar_t is 16 bits on Windows, not variable-width. If your source data is UTF8-encoded as char*, you should first convert it to wchar_t* to work with it.