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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T22:25:13+00:00 2026-05-14T22:25:13+00:00

First question on stackoverflow :) Hope I won’t embarrass myself… I have a javascript

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First question on stackoverflow 🙂 Hope I won’t embarrass myself…

I have a javascript function that loads a list of albums and then it creates a list item for each album. The list item should be clickable, so I call jQuery’s click() with a function that does stuff. I do this in a loop. My problem is that all items seem to get the same click function, even though I try to make a new one that does different stuff in each iteration. Another possibility is that the iteration variable is global somehow, and the function refers to it. Code below. debug() is just an encapsulation of Firebug’s console.debug().

function processAlbumList(data, c) {
 for (var album in data) {
  var newAlbum = $('<li class="albumLoader">' + data[album].title + '</li>').clone();
  var clickAlbum = function() {
   debug("contents: " + album);
  };
  debug("Album: " + album + "/" + data[album].title);
  $('.albumlist').append(newAlbum);
  $(newAlbum).click(clickAlbum);
 }
}

Here is a transcript of what it prints when the above function runs, after that are some debug lines caused by me clicking on different items. It always prints “10”, which is the last value that the album variable takes (there are 10 albums).

Album: 0/Live on radio.electro-music.com
Album: 1/Doodles
Album: 2/Misc Stuff
Album: 3/Drawer Collection
Album: 4/Misc Electronic Stuff
Album: 5/Odds & Ends
Album: 6/Tumbler
Album: 7/Bakelit 32
Album: 8/Film
Album: 9/Bakelit
Album: 10/Slow Zoom/Atomic Heart
contents: 10
contents: 10
contents: 10
contents: 10
contents: 10

Any ideas? Driving me up the wall, this is. 🙂

/Stefan

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  1. Editorial Team
    Editorial Team
    2026-05-14T22:25:13+00:00Added an answer on May 14, 2026 at 10:25 pm

    You need to introduce another scope, such as like this:

    var clickAlbum = (function (a) {
        return function () {
            debug("contents: " + a)
        };
    })(album);
    
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