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Home/ Questions/Q 749613
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T14:27:17+00:00 2026-05-14T14:27:17+00:00

First some code: import java.util.*; //… class TicTacToe { //… public static void main

  • 0

First some code:

import java.util.*;
//...

class TicTacToe 
{
//...

public static void main (String[]arg) 
{ 

    Random Random = new Random() ; 
    toerunner () ; // this leads to a path of 
                   // methods that eventualy gets us to the rest of the code 
} 
//... 

public void CompTurn (int type, boolean debug) 
{ 
//...

        boolean done = true ; 
        int a = 0 ; 
        while (!done) 
        { 
            a = Random.nextInt(10) ;
            if (debug) { int i = 0 ; while (i<20) { System.out.print (a+", ") ; i++; }} 
            if (possibles[a]==1) done = true ; 
        } 
        this.board[a] = 2 ; 


}
//...

} //to close the class 

Here is the error message:

TicTacToe.java:85: non-static method nextInt(int) cannot be referenced from a static context
            a = Random.nextInt(10) ;
                      ^

What exactly went wrong? What does that error message “non static method cannot be referenced from a static context” mean?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T14:27:18+00:00Added an answer on May 14, 2026 at 2:27 pm

    You are calling nextInt statically by using Random.nextInt.

    Instead, create a variable, Random r = new Random(); and then call r.nextInt(10).

    It would be definitely worth while to check out:

    • What is the reason behind "non staticmethod cannot be referenced from a static context"?

    Update:

    You really should replace this line,

    Random Random = new Random(); 
    

    with something like this,

    Random r = new Random();
    

    If you use variable names as class names you’ll run into a boat load of problems. Also as a Java convention, use lowercase names for variables. That might help avoid some confusion.

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