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Home/ Questions/Q 6690165
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T05:36:17+00:00 2026-05-26T05:36:17+00:00

first time trying to deal with this call_user_func_array, but something isn’t working, since I

  • 0

first time trying to deal with this call_user_func_array, but something isn’t working, since I get no response from the function, what can I be missing?

function _a_($id, $text) {          
    if($id == 'a') {
    _b_();
    if(substr($text, 0, 8) == "{source}") {
        $campos = substr_replace($text, '', 0, 8);
        $campos = substr($campos, 0, -9);
        $funcao = explode(";", $campos);
        print_r($funcao);
        call_user_func_array($funcao[0], $funcao[1]);
    }
    } else {
        echo $text."<br>";
    }
}
function _b_() {
    echo "b was fired<br>";
}
function _c_($some_text) {
    echo "received a call<br>";
    echo "inside function c: ".$some_text."<br>";
}
_a_("a", "{source}_c_;ola{/source}");
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T05:36:17+00:00Added an answer on May 26, 2026 at 5:36 am
    call_user_func_array($funcao[0], $funcao[1]); 
    

    =>

    call_user_func_array($funcao[0], array($funcao[1]));
    
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