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Home/ Questions/Q 59773
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Asked: May 10, 20262026-05-10T18:03:28+00:00 2026-05-10T18:03:28+00:00

First, two examples: // This works int foo = 43; long lFoo = foo;

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First, two examples:

// This works int foo = 43; long lFoo = foo;  // This doesn't object foo = (int)43; long? nullFoo = foo as long?; // returns null long lFoo = (long)foo; // throws InvalidCastException if (foo.GetType() == typeof(int))     Console.WriteLine('But foo is an int...'); // This gets written out 

Now, my guess as to why the second doesn’t work is because of boxing. The purpose behind this code is to implement IComparable. I need some way to coerce an object into either a long or a ulong as appropriate, or if it’s neither, than to throw an error. I don’t want to have to implement checks for each basic numeric type (byte, int, long, ubyte, …) I’d rather just catch them in the largest numeric type and deal with it that way. Thoughts from all the smart people here? How can I unbox the object, preferably avoiding reflection, but I suppose if that’s the only way… Or should I just not implement the non-generics version of IComparable?

Edit:

This seems to work, but seems like a horrible hack around the problem. Is it just me?

long lFoo = long.Parse(foo.ToString()); 
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  1. 2026-05-10T18:03:29+00:00Added an answer on May 10, 2026 at 6:03 pm
    object foo  = (int) 43; long   lFoo = ((IConvertible) foo).ToInt64(null); 
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  • added an answer This is expected behaviour. From the C++ standard: If no… May 11, 2026 at 11:42 am
  • added an answer The best way would probably be to use regular expressions. May 11, 2026 at 11:42 am
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