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Home/ Questions/Q 8838189
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T09:55:37+00:00 2026-06-14T09:55:37+00:00

Firstly, i’ll explain a short scenario; As a signal from certain devices triggers, an

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Firstly, i’ll explain a short scenario;

As a signal from certain devices triggers, an object of type Alarm is added to a queue. At an interval, the queue is checked, and for each Alarm in the queue, it fires a method.

However, the problem i’m running into is that, if an alarm is added to the queue whilst it’s being traversed, it throws an error to say that the queue has changed whilst you were using it. Here’s a bit of code to show my queue, just assume that alarms are being constantly inserted into it;

public class AlarmQueueManager
{
    public ConcurrentQueue<Alarm> alarmQueue = new ConcurrentQueue<Alarm>();
    System.Timers.Timer timer;

    public AlarmQueueManager()
    {
        timer = new System.Timers.Timer(1000);
        timer.Elapsed += new System.Timers.ElapsedEventHandler(timer_Elapsed);
        timer.Enabled = true;
    }

    void timer_Elapsed(object sender, System.Timers.ElapsedEventArgs e)
    {
        DeQueueAlarm();
    }

    private void DeQueueAlarm()
    {
        try
        {
            foreach (Alarm alarm in alarmQueue)
            {
                SendAlarm(alarm);
                alarmQueue.TryDequeue();
                //having some trouble here with TryDequeue..

            }
        }
        catch
        {
        }
    }

So my question is, how do i make this more…thread safe? So that i won’t run into these issues. Perhaps something along the lines of, copying the queue to another queue, working on that one, then dequeueing the alarms that were dealt with from the original queue?

edit: just been informed of concurrent queue, will check this out now

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T09:55:38+00:00Added an answer on June 14, 2026 at 9:55 am
    private void DeQueueAlarm()
    {
        Alarm alarm;
        while (alarmQueue.TryDequeue(out alarm))
            SendAlarm(alarm);
    }
    

    Alternatively, you could use:

    private void DeQueueAlarm()
    {
        foreach (Alarm alarm in alarmQueue)
            SendAlarm(alarm);
    }
    

    Per the MSDN article on ConcurrentQueue<T>.GetEnumerator:

    The enumeration represents a moment-in-time snapshot of the contents of the queue. It does not reflect any updates to the collection after GetEnumerator was called. The enumerator is safe to use concurrently with reads from and writes to the queue.

    Thus, the difference between the two approaches arises when your DeQueueAlarm method is called concurrently by multiple threads. Using the TryQueue approach, you are guaranteed that each Alarm in the queue would only get processed once; however, which thread picks which alarm is determined non-deterministically. The foreach approach ensures that each racing thread will process all alarms in the queue (as of the point in time when it started iterating over them), resulting in the same alarm being processed multiple times.

    If you want to process each alarm exactly once, and subsequently remove it from the queue, you should use the first approach.

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