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Home/ Questions/Q 8687611
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T23:09:36+00:00 2026-06-12T23:09:36+00:00

Flailing around here, seems simple. Have a Seq[Tuple2[A,B]] , call it foo, and I’d

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Flailing around here, seems simple.

Have a Seq[Tuple2[A,B]], call it foo, and I’d like to extract the Tuple2 into a (Seq[A],Seq[B]) that I can do a one stop shop multi-assignment on.

val(a,b) = foo ??

Tried map, flatmap and other variations of fail.

Shed the light if you will 😉

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  1. Editorial Team
    Editorial Team
    2026-06-12T23:09:38+00:00Added an answer on June 12, 2026 at 11:09 pm

    Try unzip.

    The docs specify it as

    def unzip[A1, A2](implicit asPair: (A) ⇒ (A1, A2)): (Seq[A1], Seq[A2])
    

    So you can just say val (a, b) = foo.unzip

    To go the other way (from x: Seq[A] and y: Seq[B] to z: Seq[(A,B)]), you can use val z = x.zip(y).

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