Question

$flr = preg_replace("/\\\'/","%27",$flr);

If url has this symbol: ‘ it got replaced by %27 and url should become http://localhost/%27
But this doesn’t work. For example:

$flr = preg_replace("/\\\"/","%22",$flr);

url replacment works and i get http://localhost/%22

Then why first example doesn’t work ?

To test i’m using:

function isValidFLR(&$flr) {
  $flr = preg_replace("/\\\'/","%27",$flr);
  $flr = preg_replace("/\\\"/","%22",$flr);
  echo $flr;
  die();
}

Answer 1

$flr = preg_replace("/'/","%27",$flr);

will work.

But, as others have said, one of the PHP functions which does this could be a better solution.